12x^2+24x-231=0

Solution for 12x^2+24x-231=0 equation:

12x^2+24x-231=0

a = 12; b = 24; c = -231;
Δ = b2-4ac
Δ = 242-4·12·(-231)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-108}{2*12}=\frac{-132}{24}
=-5+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+108}{2*12}=\frac{84}{24}
=3+1/2
$